Mile and Time Downwind Distance

1. A flat travels from Orlando to Denver and back again. On the five-hour expedition from Orlando to Denver, the skim over has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the induce of the airplane in still air? X = pep pill of plane in still air (x+40) = speed of plane leeward (x-40) =speed of plane against the wind distance = speed *travel time downwind distance = headwind distance 5(x+40) = 6(x-40) 5x+200=6x-240 6x-5x=240+200 x=440 mphSo, The speed of the plane in still air is 440 mph if I am not mistaken. 2. Two bicycles depart from Miami B distributively going in opposite directions. The prototypical bicycle is traveling at 10 miles per hour. The second bicycle travels at 5 miles per hour. How long does it take until the bikes are 45 miles apart? D=RT 45=(10+5)T 45=15T T=445/15 T=3 hours. 3. Jesse rents a moving van for $75 and must pay $2 per mile. The sid eline week, Alex rents the same van, is charged $80 for the rental and $1. 50 per mile. If they distributively give the same sum and drove the same number of miles, how far did they each travel? 5+2m=80+1. 5m lift off 75 from both sides subtract 1. 5m from both sides .5m=5 multiply both sides by 2 m=10 miles . 4. During a 4th of July weekend, 32 vehicles became trapped on the temperateness Skyway Bridge while it was being repaved. A recent urban center ordinance decreed that scarce cars with 4 wheels and trucks with six wheels could be on the bridge at any given time. If there were 148 tires that needed to be replaced to due to damage, how many cars and trucks were involved in the incident? Okay. There were 32 cars , we have x + y = 32 ars have 4 wheels so 4x , trucks have 6 wheels so 6x the total number of wheels adds up to 148, so 4x +6y = 14 x+y=32 4x + 6y = 148 -4x 4y = -128 4x + 6y = 148. 5. For this question, you will need a parent/guardian or a friend. Have this indiv idual gingersnap a handful of coins making sure there are only two types of coins in the group (i. e. , nickels and dimes, quarters and pennies, pennies and dimes, etc). Your parent/guardian or friend should tell you the type of coins theyve chosen, how many coins they have and the dollar amount of the group.From this information, you will set up two sets of equations and determine how many of each coin they have in their hand. Please send your instructor the cook of the individual who helped you with this question, your two equations and the work you did to solve the system. She has 11 coins worth 83 cents. P and Q will the number of pennies and quarters, P + Q = 11 P + 25Q = 83 P + 25Q P + Q = 24 Q = 83 11 = 72. So, 24 Q = 72 Q = 3. Q = 3 can be put into the equation to solve for P. If we character the first equation, we get P + 3 = 11 P = 8, so three quarters and eight pennies.